Hey there!
12/14
• BOTH NUMBERS HAVE THE COMMON FACTOR OF 2, SO WE CAN DIVIDE BOTH THE NUMERATOR (TOP number) FROM THE DENOMINATOR (BOTTOM number)
= 12 ÷ 2 / 14 ÷ 2
= 6/7
= 18/21
Therefore, your answer is: 6/7 or 18/21
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
The answer is 258 pennies
Answer: i will say About $23.77 per hour.
Step-by-step explanation:
i hope this help btw good luck
