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vfiekz [6]
3 years ago
6

If f(x)= x2 + 2x - 6 and g(x)= 3x2 - 5x - 7, find f(x)-g(x).

Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

- 2x² + 7x + 1

Step-by-step explanation:

f(x) - g(x)

= x² + 2x - 6 - (3x² - 5x - 7) ← distribute parenthesis by - 1

= x² + 2x - 6 - 3x² + 5x + 7 ← collect like terms

= - 2x² + 7x + 1

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If f(x) = 3^2 + 10x and g(x) = 2x-4, find (f-g)(x).
Marat540 [252]

What we know:      

f(x)=3^2+10x\\g(x)=2x-4                

(Also, 3^2=9)

What we need to solve:

(f-g)(x)             (This is equal to f(x)-g(x))

How you have to subtract f(x) with g(x) to get:

(f-g)(x) = f(x)-g(x) = 9+10x+2x-4 = 12x+5

Thus, the answer would be:

12x+5

3 0
2 years ago
A gas pump fills 2^-2 gallon of gasoline per second. how many gallons does the pump fill in one minute?
astraxan [27]

Answer:

The gas pump filling the gallons in 1 minute will be: 15

Step-by-step explanation:

  • Given that a gas pump fills 2^-2 gallon of gasoline per second.

As there are 60 seconds in 1 minute.

Thus,

Gas pump filling the gallons in 1 minute will be:

60\:\times 2^{-2}

=60\times \frac{1}{2^2}             ∵ a^{-b}=\frac{1}{a^b}

\mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c}

=\frac{1\times \:60}{2^2}

=\frac{60}{2^2}

=\frac{2^2\times \:3\times \:5}{2^2}

=3\times \:5

=15 gallons in one minute

Therefore, the gas pump filling the gallons in 1 minute will be: 15

6 0
2 years ago
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