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ankoles [38]
3 years ago
7

Just do numbers 1-6,22-24, and 25-26

Mathematics
1 answer:
Paul [167]3 years ago
7 0

1. 0.625

2. 0.22222222222

3. 0.43243243243

4. -0.11111

5. 0.54

6. -0.75

22. −2 21/50

23. -4/25

24. -13/20

25. 0.62

26. 7/15

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You pick a card at random.
natima [27]

The most appropriate choice for Probability of an event will be given by-

P(7) = \frac{1}{3}

What is Probability?

Probability gives us the information about how likely an event is going to occur

Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.

Probability of any event is greater than or equal to zero and less than or equal to 1.

Probability of sure event is 1 and probability of unsure event is 0.

Here,

Sample space = {6, 7, 8}

Total number of outcomes = 3

Favourable outcomes = {7}

Number of favourable outcomes = 1

Probability of getting a 7 = P(7) = \frac{1}{3}

To learn more about probability of an event, refer to the link:

brainly.com/question/251701

#SPJ9

4 0
2 years ago
Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5
iVinArrow [24]

Answer:

h(x)=-2x+4

g(x)=\sqrt[3]{x}-5

Step-by-step explanation:

Consider the given function is

f(x)=\sqrt[3]{-2x+4}-5

It is given that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x.

f(x)=\sqrt[3]{(-2x+4)}-5

Let h(x)=-2x+4, then we get

f(x)=g(h(x))=\sqrt[3]{h(x)}-5

Substitute h(x)=x in the above function.

g(x)=\sqrt[3]{x}-5

Therefore, the required functions are h(x)=-2x+4 and g(x)=\sqrt[3]{x}-5.

Check the solutions.

g(h(x))=g(-2x+4)             [\because h(x)=-2x+4]

g(h(x))=\sqrt[3]{-2x+4}-5            [\because g(x)=\sqrt[3]{x}-5]

g(h(x))=f(x)

Therefore, our solution is correct.

7 0
4 years ago
Choose the linear equations.
andrew-mc [135]

Answer:

y = \frac{3}{3}x - 5

y = 2x + 5

Step-by-step explanation:

In linear equations, both variables x and y must have the exponent of 1 (i.e. they cannot have a small number at the top-right). And they cannot be in the exponents (i.e. cannot be the small number at the top-right).

7 0
3 years ago
Line I passes through point (-1,2). Which of the following CANNOT be the equation
mamaluj [8]

Answer:

confusion

Step-by-step explanation:

5 0
3 years ago
A triangle can be formed having side lengths $4,$ $5,$ and $8.$ It is impossible, however, to construct a triangle with side len
Zanzabum

14  triangles with exactly two equal sides can be formed

The triangles will be isosceles as there have to be 2 equal sides.

The possible triangles are :

2 2 3      3 3 2        5 5 2       7 7 2         11  11  2

             3 3 5        5 5 3       7 7 3         11  11  3

                             5 5 7       7 7 5         11  11  5

                                            7 7 11       11  11  7

So 14   triangles are possible

To know more about triangles visit: brainly.com/question/1058720

#SPJ4

4 0
3 years ago
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