All categories

2 years ago

Just do numbers 1-6,22-24, and 25-26

Mathematics

1 answer:

Paul [167]2 years ago

7 0

1. 0.625

2. 0.22222222222

3. 0.43243243243

4. -0.11111

5. 0.54

6. -0.75

22. −2 21/50

23. -4/25

24. -13/20

25. 0.62

26. 7/15

You might be interested in

What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3

Gnoma [55]

Answer:

√30-√18+√55-√33/2

Step-by-step explanation:

What is the following quotient? sqrt6+sqrt11/sqrt5+sqrt3

Given the expression

√6+√11/√5+√3

Rationalize

√6+√11/√5+√3 × √5-√3/√5-√3

= √30-√18+√55-√33/√25-√9

= √30-√18+√55-√33 /5-3

= √30-√18+√55-√33/2

This gives the required quotient

6 0

2 years ago

I was taught how to do these I just don’t remember how to-3(4x+5)-2(-5x+8)

frosja888 [35]

Answer:

- 2x - 31

Step-by-step explanation:

Given

- 3(4x + 5) - 2(- 5x + 8)

Multiply the terms in the first parenthesis by - 3 and the terms in the second parenthesis by - 2

= - 12x - 15 + 10x - 16 ← collect like terms

= (- 12x + 10x) + (- 15 - 16)

= - 2x - 31

6 0

3 years ago

Six to the third power times six to the fourth power in exponential form

Marta_Voda [28]

Answer:

$6^7$

Step-by-step explanation:

<u>Step 1: Convert</u>

Six to the third power times six to the fourth power.

$6^3 * 6^4$

$6^(^3^+^4^)$

$6^7$

Answer: $6^7$

3 0

3 years ago

Read 2 more answers

10. Given that the total distance travelled is 4 km and that the initial aceleration is 4 m/s², find:a) the value of V.b) the va

andrezito [222]

The initial deceleration is 4 m/s^2, so this means that considering the first line segment, $\frac{V-100}{T}=-4 \implies V=100-4T$ .

The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so $400T-\frac{1}{2}(100-V)(5T)=4000$ .

$400(100-4T)-\frac{1}{2}(4T)(5T)=4000\\\\40000-1600T-10T^2=4000\\\\10T^2 +1600T-36000=0\\\\T^2 +160T-3600=0\\\\(T+180)(T-20)=0\\\\T=20 (T > 0)\\\\\therefore V=100-4(20)=20$