Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
A.
Step-by-step explanation:
A box-and-whisker plot. Hope this helps! :)
let length of the rectangle be l
length is 6 cm longer than the width, w
l = w + 6
perimeter of rectangle is 72 cm
= 2l + 2w
substitute l = w + 6
2(w+6) + 2w = 72
4w + 12 = 72
4w = 60
x = 15
ans is C. 15 cm
