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Yanka [14]
3 years ago
11

Simplify 8^3 divided by 4^2. A.) 2 B.) 3 C.) 33

Mathematics
2 answers:
N76 [4]3 years ago
7 0

Answer:

32

Step-by-step explanation:

\frac{8^{3}}{4^{2}} = \frac{512}{16} = 32

puteri [66]3 years ago
6 0

Answer:

32.

Step-by-step explanation:

8^3/4^2

First, simplify the exponents by converting the exponents into numbers.

8^3=512

4^2=16

Lastly, divide as normal.

512/16=32

Therefore, 8³ ÷ 4² = 32.

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An older person is 4 years older than 7 times the age of a younger person. The sum of their ages is 44. Find their ages
Fynjy0 [20]

Answer:

5 yr and 39 yr

Step-by-step explanation:

Let x = the age of the younger

then 7x + 4 = the age of the older

Now x + 7x + 4 = 44

8x + 4 = 44

8x = 40

x = 5

7x + 4 = 7(5) + 4 =  35 + 4 = 39

Check:  5 + 39 = 44

8 0
2 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

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We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

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1 year ago
Select the equation that most accurately depicts the word problem. One-half of a certain number is 95.
Anastaziya [24]

Answer:

you would only need to add or multiply the numbers

Step-by-step explanation:

some of the equations could be-

95+ x =190

95 x 2 =190

x / 2 = 190

5 0
3 years ago
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Assoli18 [71]

Answer:

The correct answer is -1

4 0
3 years ago
Read 2 more answers
What is the standard form of 0.0005?
mash [69]

5 * 10 raise to power of - 4

7 0
2 years ago
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