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mezya [45]
3 years ago
15

3a − 2a + 4 = 16 Solve for a.

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

a=12

Step-by-step explanation:

3a-2a+4=16\\\\(3a-2a)+4=16\\\\(3-2)a+4=16\\\\1a+4=16\\\\a+4-4=16-4\\\\a=12

Hitman42 [59]3 years ago
3 0

Answer:

12

Step-by-step explanation:

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Rewrite each fraction in simplest form using the GCF of the numerator and denominator.
Elanso [62]

Answer:

\sf 6. \quad \dfrac{7}{10}

\sf 7. \quad \dfrac{5}{17}

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 42 = 2 × 3 × 7
  • 60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF:  2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 80 = 2 × 2 × 2 × 2 × 5
  • 272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF:  2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}

5 0
1 year ago
Read 2 more answers
144x^{2}[/tex]-169<img src="https://tex.z-dn.net/?f=-y%5E%7B2%7D" id="TexFormula1" title="-y^{2}" alt="-y^{2}" align="absmiddle"
Ainat [17]

Answer:

144x^2−y^2−169 because ther are no like terms

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the answers
Mice21 [21]
Angle 2 is 110° and the other angles are 70°
4 0
3 years ago
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Which is the correct calculation for the volume of the prism?
ira [324]

Answer: i think its B

Step-by-step explanation:

8 0
3 years ago
sally has a piggy bank with $10 in it. She counted 68 coins of only quarters and nickles. How many nickles are in her piggy bank
UkoKoshka [18]

Answer:

n=35; q=33 coins.

Step-by-step explanation:

1) if number of nickles is 'n' and the quaters is 'q' then it is possible to write:

n+q=68 - 'she counted 68 coins...' - the 1st equation of system;

0.25q+0.05n=10 - '10$ in it' - the 2d equation of the system.

2) it is possible to make up and solve the next system of two equations:

\left \{ {{q+n=68} \atop {0.25q+0.05n=10}} \right. \ => \ \left \{ {{q=33} \atop {n=35}} \right. .

7 0
2 years ago
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