F(x) = 3x + 1
let f(x) = y
y = 3x + 1
y - 1 = 3x
3x = y - 1
x = (y - 1)/3
From y = f(x), x = f⁻¹(y)
<span>x = (y - 1)/3
</span>
f⁻¹(y) = (y - 1)/3
f⁻¹(7) = <span>(7 - 1)/3 = 6/3 = 2
</span>f⁻¹(7)<span> = 2</span>
Answer: y=5x
Step-by-step explanation:
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To solve this find the common number that can be divided by both and use that number.
In this case, 4 is divisible by both 4 and 12, and thus the final expression would be
4(d + 3e).
<u>Given</u>:
Given that ABCD is a rectangle.
The diagonals of the rectangle are AC and DB.
The length of AE is (6x -55)
The length of EC is (3x - 16)
We need to determine the length of the diagonal DB.
<u>Value of x:</u>
The value of x can be determined by equating AE and EC
Thus, we have;

Substituting the values, we get;




Thus, the value of x is 13.
<u>Length of AC:</u>
Length of AE = 
Length of EC = 
Thus, the length of AC can be determined by adding the lengths of AE and EC.
Thus, we have;



Thus, the length of AC is 46.
<u>Length of DB:</u>
Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.
Hence, we have;


Thus, the length of DB is 46.