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3 years ago

Kelly’s Experimental Outcomes

Mathematics

1 answer:

maria [59]3 years ago

5 0

Answer:

60% or 3/5

Step-by-step explanation:

Tails was the result 3 times.

There were 5 trials.

The probability is 3/5.

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Solve -12 = z ÷ 3 for z.

Andrew [12]

Answer:

-4 i think

Step-by-step explanation:

divide -12 by 3 to get -4

3 0

3 years ago

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Adana has 4 skirts, 3 blouses, and

Bumek [7]

Adama can make 7 outfits

6 0

3 years ago

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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$

Thus, the system of three equations is

$\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.$

From the last equation:

$y=-6$

Substitute it into the second equation:

$16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3$

Substitute y = -6 and z = -3 into the first equation:

$x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5$

7 0

3 years ago

4. A triangle has angle measures of 72º and 3°. What is the measure of the third angle?

8090 [49]

Answer:

105

the whole triangle adds up to 180

72+3=75

180-75=105

7 0

2 years ago

3. Use the diagram to answer the following questions.

Nuetrik [128]

Answer:

See explanation

Step-by-step explanation:

A. There are 8 points: A, B, C, D, E, F, G and H

B. There are 9 lines in the figure: AB, BC, AC, DE, DF, EF, BE, AD and CF

C. There are 5 planes in the figure: ABC, DEF, ABED, ACFD and BEFC

D. Three points are collinear if they lie on the same line. Collinear points are D,G and F or C,H and F

E. Coplanar points are those which lie in the same plane. Coplanar points are B, E, F and C or A, C, F and D or A, B, E and D or other combinations of four points lying in the same plane

I. Planes ABC and ABE intersect by a line AB

G. Planes BCH and DEF intersect by a line EF

H. Lines AD and DF intersect at a point D

4 0

3 years ago