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3 years ago

What is 32.03 in expanded form

1 answer:

5 0

When you write a number in expanded form, you separate the digits based on their place value and turn it into an addition expression. The answer is 30+2+0.0+0.03, or if your teacher doesn't require the extra 0.0, just remove it.
Hope that helped.

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Please help me with steps

Kitty [74]

Answer:

12 if x_y

Step-by-step explanation:

12= 3x4 (I'm sorry for this, I need points)

8 0

3 years ago

Will give brainliest!!! Please help and explain!!!

oee [108]

Answer:

6 * squ 2

Step-by-step explanation:

squ 6 * squ 12 = squ 6*12 = squ 72 = squ 36 * 2 = 6 * squ 2

6 0

3 years ago

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as

mamaluj [8]

Answer:

The farmer have at first 202 chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be $x.$

And, the ducks be $y.$

As, the farmer had twice as many chickens as ducks on his farm.

So, $x=2y$ ......(1)

As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.

According to question:

$x-166=(y-29)\times \frac{1}{2}$

$x-166=\frac{y-29}{2}$

Substituting the value of $x$ from equation (1) we get:

$2y-166=\frac{y-29}{2}$

By cross multiplying we get:

$4y-332=y-29$

Adding both sides 332 we get:

$4y=y+303$

Subtracting both sides by $y$ we get:

$3y=303$

Dividing both sides by 3 we get:

$y=101.$

Now, to get the number of chickens substituting the value of $y$ in equation (1):

$x=2y\\\\x=2\times 101\\\\x=202.$

Therefore, the farmer have at first 202 chickens.

7 0

3 years ago

three numbers are in an arithmetic progression. Their sum is 3 and the sum of their squares is 11. what are the three numbers

Vlad [161]

The three numbers are 12, 18 and 24

Arithmetic progression

Let the 3 number in arithmetic progression be:

a-d, d, a+d ...

If their sum is 3, then;

a-d+d+a+d = 3

2a + d = 3 ........... 1

If the sum of their squares is 11, then;

(a-d)² + d² + (a+d)² = 11

a²-2ad+d²+d²+a²+2ad+d² 11

2a²+3d² = 11 ....... 2

Solving the equations simultaneously, d = 6 and a = 12

First-term = 12

second term = 18

Thirs term = 24

Hence the three numbers are 12, 18 and 24

Hope this helps you!!!!!! :D

5 0

2 years ago

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Need this one ASAP please

babunello [35]

Answer:

28..

Step-by-step explanation:

divide 35 by 1 1/4...

7 0

3 years ago

Read 2 more answers