Which expression is equivalent to one over fivem − 20?

Mathematics

2 answers:

Len [333]3 years ago

6 0

Answer:

$\large\boxed{\dfrac{1}{5(m-4)}}$

Step-by-step explanation:

One (1) over (fraction) five m (5m) - 20:

$\dfrac{1}{5m-20}$ <em>distributive</em>

$\dfrac{1}{(5)(m)-(5)(4)}=\dfrac{1}{5(m-4)}$

weeeeeb [17]3 years ago

4 0

Answer:

I'd say 1/5- 4m

Step-by-step explanation:

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g Let G be a not necessarily abelian group with normal subgroups H and K such that H contains K (i.e., K ✂ G, H ✂ G, K ≤ H) and

allsm [11]

Answer:

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3 years ago

Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?

murzikaleks [220]

Answer:

$cos(\theta)=-\frac{\sqrt{35} }{6}$

Step-by-step explanation:

Recall the negative angle identity for the sine function:

$sin(- \theta)=-sin(\theta)$

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$sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}$

Now recall the definition of the tangent function:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Therefore, now that we know the value of $sin(\theta)$ , we can solve in this equation for $cos(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}$