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lyudmila [28]
2 years ago
7

Which expression is equivalent to one over fivem − 20?

Mathematics
2 answers:
Len [333]2 years ago
6 0

Answer:

\large\boxed{\dfrac{1}{5(m-4)}}

Step-by-step explanation:

One (1) over (fraction) five m (5m) - 20:

\dfrac{1}{5m-20}    <em>distributive</em>

\dfrac{1}{(5)(m)-(5)(4)}=\dfrac{1}{5(m-4)}

weeeeeb [17]2 years ago
4 0

Answer:

I'd say 1/5- 4m

Step-by-step explanation:

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You have 2 equations that are both equal to y. If they are both equal to y, then by the transitive property of equality, they are equal to each other (if a = b, and b = c, then a = c).
5x - 17 = x + 3 and
4x = 20 and x = 5. Now sub in that x value of 5 to solve for y:
y = 5 + 3 and y = 8. So the ordered pair is (5, 8)
5 0
2 years ago
Can someone explain (with steps) how to rationalize the following expression?
insens350 [35]
F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
6 0
3 years ago
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