Answer:
Your answer is c
Step-by-step explanation:
the two inequalities are x =< 1 and x =>2 which is shown by the number line in option c
Answer:
B
Step-by-step explanation:
This is the correct answer because the difference between 32 and 29 is 3 and the intial price is 32, Hence 3/32 (100)
Answer
The expression is equivalent to sin^{2}x
The first step is to multiply the two expressions between parentheses :
(II)
There is a trigonometric identity that states :
Working with this expression :
⇒
(I)
Using the equation (I) in (II) :
⇒
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After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.
After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.
And so on. After t years, the investment would have a value of
.
We want the find the number of years n such that

Solve for n :




