Answer:
1931.7N
Step-by-step explanation:
We are told in the question that :
An auto ( a car) weighs = 2500 pounds
It s inclined at n horizontal Ange of 10°
We are asked to find the force that would prevents it from rolling down the street.
Since the unit for Force = Newton or kgm/s²
Step 1
Convert Weight in pounds to kg
1 pound = 0.453592kg
2500 pounds =
2500 pounds × 0.453592kg
= 1133.981kg
Step 2
Find the force that would prevents it from rolling down the street.
Force = Mass × Acceleration due to gravity × sin θ
Acceleration due to gravity = 9.81m/s
Force = 1133.981kg × 9.81 × sin 10°
Force = 1931.7237321 N
Approximately = 1931.7N
Answer: indistinct, alike equivelent
Step-by-step explanation:
7<n<8 is the right answer
(2x²<span> + 3x - 4) + (8 - 3x) + (-5x</span>²<span> + 2)
= </span> 2x² + 3x - 4 + 8 - 3x - 5x² + 2
= -3x² + 6
= 3(-x² + 2)
93/4
9/4=2r1
13/4=4r1
10/4=2r2
20/5=4
=23.25
