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3 years ago

Three coins are tossed. find the probability that two lands on heads

Mathematics

1 answer:

NeX [460]3 years ago

8 0

Only 1 coin lands on tales of 2 coins landed on heads

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Which algebraic expression is a polynomial?

Degger [83]

Answer:

the last one is a polynomial

Step-by-step explanation:

8 0

2 years ago

Parker reviews his homework before he turns it in. When he sees the equation 1.02 divided by 0.6= 0.17, he knows it is wrong. He

HACTEHA [7]

Answer:

The result of the division of a number by a fraction is larger than the fraction.

Step-by-step explanation:

Here,we note that value Parker divided by 0.6. =1.02

Written down result of the division = 1.02/0.6 = 0.17

However, since the numerator is 1.02, then the result of dividing it by a fraction should yield a higher number instead of 0.17

Therefore we check as follows

1.02/0.6 = 1.7

The error is apparently due to dividing 1.02 by 6 rather than 0.6

3 0

3 years ago

Which value of x does not satisfy the equation sin^2x + sin x = 0

zzz [600]

Answer:

$x \neq 0 \pm \pi \cdot i, \forall i \in \mathbb{N}_{O}$ and $x \neq \frac{3\pi}{2}\pm 2\pi \cdot j, \forall j \in \mathbb{N}_{O}$ .

Step-by-step explanation:

The equation can be simplified with the help of trigonometric identities:

$\sin x \cdot (\sin x + 1) = 0$

Which means that equation is equal to zero if any component of the product is zero. The solutions of the expression are:

a) $\sin x$

$x = 0 \pm \pi\cdot i,\forall i \in \mathbb{N}_{O}$

b) $\sin x + 1$

$\sin x + 1 = 0$

$\sin x = -1$

$x = \frac{3\pi}{2} \pm 2\pi\cdot i,\forall i \in \mathbb{N}_{O}$

Any value different of both subsets do not satisfy the equation described above.

8 0

3 years ago

A store makes a profit of $15 on a wallet, after a mark up of 60%, what is the selling price of the wallet ?

Radda [10]

1.5 multiplied by 6 equals 9

3 0

3 years ago

If Upper A equals StartSet x | x is an even integer EndSet commaA={x | x is an even integer}, Upper B equals StartSet x | x is a

White raven [17]

Answer:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Step-by-step explanation:

A={x | x is an even integer}

B={x | x is an odd integer},

C={2, 3, 4, 5},

D={8, 9, 10, 11}.

A union of two or more sets is the collection of the members of the sets in a set without repeating any element.

Given sets C and D above, the union of the two sets is the set:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Note: The Intersection is the collection of sets that are common to C and D. in this case no element is common, therefore the intersection is a Null Set.

8 0

3 years ago