All categories

2 years ago

The number of bacteria present in a laboratory

Mathematics

2 answers:

Gala2k [10]2 years ago

8 0

Answer:

B. 500

good luck

Reil [10]2 years ago

7 0

Answer:

The answer is B.500

Step-by-step explanation:

The original equation containing unknown variables would be 500(t) (with "t" representing the number of days)

So if you fill the variable in with a 2, that means it's been 2 days with the increase of 500 bacteria each day.

That means the initial number of bacteria must be 500.

If it's been 2 days and you want to determine the bacteria number, then multiply 500 by 2 and you get yourself 1000 bacteria.

You might be interested in

Please help me pleeeeeease

adell [148]

Your answer is B or #2 out of the possible answers

6 0

2 years ago

Read 2 more answers

If you are doing area in mathematics and the base is 16 and the height is 5 but there are 4 sides, don't u need to multiply 16x5

Murrr4er [49]

No, you would only need to multiply 16 by 5 once

4 0

2 years ago

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

6 0

2 years ago

If Lana deposits $500 into a savings account that gains simple interest at

Oksana_A [137]

Answer:

10 years

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 2%/100 = 0.02 per year,

then, solving our equation

t = 100 / ( 500 × 0.02 ) = 10

t = 10 years

The time required to

accumulate simple interest of $ 100.00

from a principal of $ 500.00

at an interest rate of 2% per year

is 10 years.

3 0

2 years ago

The base of a circular fence with radius 10 m is given by x = 10cos(t), y = 10sin(t). the height of the fence at position (x, y)

Karo-lina-s [1.5K]

The average height of the fence is 2 m; its length is 20π m. So, its 2-sided area is
A = 2*(2 m)*(20π m) = 80π m² ≈ 251 m²

At 1 L/(100 m²), it will take 2.51 L of paint to paint both sides.

6 0

2 years ago