Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So
Given that 
normal sampling distribution can not be used
Answer:
140 toy cars
Step-by-step explanation:
The ratio of Ed's toy car to Pete's toy car is initially given as 5:2
Ed gave Pete a total number of 30 cars
Let x represent the greatest common factor that exists between both number
Number of Ed's car is represented as 5x
Number of Pete car is represented as 2x
Since they each have an equal number of cars which is 30 then we can solve for x as follows
5x-30=2x+30
Collect the like terms
5x-2x= 30+30
3x= 60
Divide both sides by the coefficient of x which is 3
3x/3=60/3
x=20
Ed's car is 5x, we substitute 20 for x
5(20)
= 100 cars
Pete car is 2x,we substitute 20 for x
2(20)
= 40 cars
Therefore, the total number of cars can be calculated as follows
= 100+40
= 140 toy cars
Hence they have 140 toy cars altogether
Answer:
y = -1, x = -2
Step-by-step explanation:
First, multiply the top equation by 2 to make 3x become 6x:
6x - 8y = -4
Second, multiply the bottom equation by 3 to make -2x become -6x:
9y - 6x = 3
Add the two equations together, and you get:
y = -1
Plug in y as -1 into the first or second equation:
3x - 4(-1) = -2
OR
3(-1) - 2x = 1
x = -2
Answer:
integer = 5
rational number but not an integer - 3 and a 1/2
irrational number - it's the one with 11
50,000 ÷ 250 = 200
This means that there are 200 seats in each section.
