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Shalnov [3]
3 years ago
13

How to solve x=6y-11 and 3x-2y=-1 by substitution

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
7 0
Substitute x into the second equation:
3(6y-11)-2y=-1
18y-33-2y=-1
16y=32
y=2
Then put the y value into the first equation to get x:
x=6(2)-11
x=1
There you go!

Please mark brainliest
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K(x) = 6x+100 k(-5) =
kkurt [141]

Answer:

k(-5)=70

Step-by-step explanation:

The given function is

k(x)=6x+100

To find k(-5), we put x=-5 into the given function to get;

k(-5)=6(-5)+100

Multiply out to obtain;

k(-5)=-30+100

This is the same as;

k(-5)=100-30

This simplifies to

k(-5)=70

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3 years ago
HELP YOUR GIRL OUT PLEASE!!
Blababa [14]

The value of the collection originally was $1,000,000

What was the original value of the collection?

The original value of the collection is not known, hence, it is represented by X

The increase in value by $50,000 means that the value is X+$50,000

Now, when the error was discovered, it is now worth half of the  value previously

The new value is (X+$50,000)*0.5

New value=(X+$50,000)*0.5

The new value at this point is $525,000

$525,000=(X+$50,000)*0.5

$525,000/0.5=X+$50,000

$1,050,000=X+$50,000

X=$1,050,000-$50,000

Find out more about change in value on:brainly.com/question/13097163

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