How to solve x=6y-11 and 3x-2y=-1 by substitution
1 answer:
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answer:X=k/n-3
explain:move all terms to the left side and set equal to zero. then set each factor equ to zero!
I hope this helps
Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is
x = μ + σz
At middle of 50% i.e 0.50
The critical value for
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days