3 years ago

Can anyone please help me on this question

Mathematics

1 answer:

Pani-rosa [81]3 years ago

4 0

5x + 3 - x - 2

4x + 1

the answer to the question is d

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2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.

marysya [2.9K]

$2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)$

$x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321$

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3 years ago

Read 2 more answers

4<br> 74<br> Solve the inequality 2(4x + 1) <3(2x - 3)

Katena32 [7]

Step-by-step explanation:

2(4x + 1) < 3(2x - 3)

8x + 2 < 6x - 9

8x - 6x < -9 -2

2x < -11

x < -11/2

8 0