Shoppers at a grand opening for a sporting goods store receive a gift bag when they make a purchase.

Mathematics

1 answer:

photoshop1234 [79]4 years ago

8 0

Answer: Every 12th bag has both a T-shirt and socks.

Step-by-step explanation:

Given: T shirt: Every fourth bag

Socks: Every third bag

Least common multiple of 4 and 3 = 12 as 4 and 3 are coprime (i.e. their highest common factor is 1) and 4 x 3 = 12

It implies every 12th bag has both a T-shirt and socks.

Hence, Every twelfth bag has both a T-shirt and socks.

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What is the answer for 9=Y=?

musickatia [10]

(5,4)

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mark brainliest :)

you question did not make sense so i assumed this is what you meant and needed.

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3 years ago

Please solve the problem with steps

Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

$\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}$

The first one: $(\frac{1}{2})^{n-1}$ is a geometric sequence of first term ( $a_1$ ) "1" and common ratio (r) " $\frac{1}{2}$ ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: $Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2$

The second one: $\frac{1}{6^{n-1}}$ is a geometric sequence of first term "1", and common ratio (r) " $\frac{1}{6}$ ". Again, since the common ratio is smaller than one, we can find its infinite sum: