|x-10| when x = -8
| - 8 - 10 | = |-18| = 18 <==
The equation that matches the given table is
y = 10x + 40
Solution:
General equation of a line : y = mx + c
Let us find the equation of the table.
<u>Common differences of X: </u>
0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1
<u>Common differences of Y: </u>
50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10


m = 10
Substitute m = 10 in general equation of a line
y = 10x + c
To find the constant term, substitute x = 0 and y = 40.
40 = 10(0) + c
40 = 0 + c
40 = c
c = 40
Therefore the equation of a line is y = 10x + 40.
Hence the equation that matches the given table is y = 10x + 40.
The equation of a line is y=-1/4x-7, (option 1)
<h3>
What is the equation of a line? </h3>
A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis.
<h3>
How do you find the equation of a line?</h3>
Write the equation in the form y = mx + b to find the slope m and the y-intercept. This will allow you to graph the equation using the slope and y-intercept.
Given:-
Equation of the line is y=4x+8
The point through which the line passes (-8,4).
here the slope of the line is m1=4
To find the perpendicular line we know the formula
m1*m2=-1
By putting the value of m1 we get m2= -1/4
By using the one-point formula of the line we have
=>(y-y1)=m2*(x-x1)
By putting the values of y1 and x1 we get
(y1,x1)=(-8,4)
=>(y+8)=-0.25*(x-4)
y+0.25x+7=0
Hence the desired equation of the line is y=-1/4x-7
To find more about the straight line equations visit :
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Answer:
$69.60
Step-by-step explanation:
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Monthly payment:

Upfront payment:
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If it’s an angle I think 90% but if not maybe 24 all around