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Anuta_ua [19.1K]
2 years ago
7

Fast brainliest for u if u fast answer

Mathematics
1 answer:
sergiy2304 [10]2 years ago
7 0

Answer:

It's 1/21

cuz if u divide them that what i got

Step-by-step explanation:

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Find the area if length is 4x, width is 9 and x is 1/3
LuckyWell [14K]

Answer:

12

Step-by-step explanation:

4 • 1/3 = 4/3

9 • 4/3 = 36/3

36/3 simplified is 12

8 0
3 years ago
Trigonometric ratios in rig triangles pls help
choli [55]

Answer:

D. 35/12

Step-by-step explanation:

\tan( \alpha ) =  \frac{35}{12}  \\

7 0
3 years ago
If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.
Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have S_1=3\times2^{1-1}+2(-1)^1=3-2=1, which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}

and

S_k=3\times2^{k-1}+2(-1)^k

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}

From the given recurrence, we know

S_{k+1}=S_k+2S_{k-1}

so that

S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)

S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}

S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)

S_{k+1}=3\times2^k-2(-1)^k

S_{k+1}=3\times2^k+2(-1)(-1)^k

\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}

which is what we needed. QED

6 0
3 years ago
Explain how the Remainder Theorem and the Factor Theorem are related.​
Daniel [21]
Basically the remainder theorem links the remainder of division by a binomial with the value of a function at a point while the factor theorem links the factors of polynomial to its zeros
8 0
3 years ago
Answer this for branlist if get right
dusya [7]

Answer:

The median and IQR

Step-by-step explanation:

4 0
2 years ago
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