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Anuta_ua [19.1K]
3 years ago
7

Fast brainliest for u if u fast answer

Mathematics
1 answer:
sergiy2304 [10]3 years ago
7 0

Answer:

It's 1/21

cuz if u divide them that what i got

Step-by-step explanation:

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Henry is planning to create two rectangular gardens.
seraphim [82]

Answer:

Step-by-step explanation:

THANKS 4 POINTS!!!!!!!

5 0
3 years ago
What is the answer i need plsss
earnstyle [38]
Do 2-1 that should work

5 0
3 years ago
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When working problems on the calculator for trig functions, what are you supposed to have your calculator set to?
9966 [12]

Answer:

Degrees

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dont need one

4 0
3 years ago
Write out the steps in solving 3/4 x 2 2/5
max2010maxim [7]
3/4 × 2 2/5

Turn 2 2/5 into an improper fraction.

2 2/5 = (5 × 2) + 2 = 12

So, 2 2/5 = 12/5

So, our new question is : 3/4 × 12/5

Multiply the numerators (top numbers) with one another.

Numerators : (3 × 12) = 36

Multiply the denominators (bottom numbers) with one another.

Denominators : (4 × 5) = 20

So, our answer is 36/20

However, we need this to be a mixed number.

So, how many times does 20 go into 36? Once!

So, Multiply 20 with 1, and then subtract that number from 36! :)

20 × 1 = 20

36 - 20 = 16

So, our answer is :

1 16/20

Then, you simplify it once more.

Divide the numerator and denominator by 4.

16 ÷ 4 = 4

20 ÷ 4 = 5

So, our final answer is 1 4/5


~Hope I helped!~
7 0
3 years ago
Read 2 more answers
What is the difference between bernoulii equation and riccati equation
melisa1 [442]
The Bernoulli equation is almost identical to the standard linear ODE.

y'=P(x)y+Q(x)y^n

Compare to the basic linear ODE,

y'=P(x)y+Q(x)

Meanwhile, the Riccati equation takes the form

y'=P(x)+Q(x)y+R(x)y^2

which in special cases is of Bernoulli type if P(x)=0, and linear if R(x)=0. But in general each type takes a different method to solve. From now on, I'll abbreviate the coefficient functions as P,Q,R for brevity.

For Bernoulli equations, the standard approach is to write

y'=Py+Qy^n
y^{-n}y'=Py^{1-n}+Q

and substitute v=y^{1-n}. This makes v'=(1-n)y^{-n}y', so the ODE is rewritten as

\dfrac1{1-n}v'=Pv+Q

and the equation is now linear in v.

The Riccati equation, on the other hand, requires a different substitution. Set v=Ry, so that v'=R'y+Ry'=R'\dfrac vR+Ry'. Then you have

y'=P+Qy+Ry^2
\dfrac{v'-R'\dfrac vR}R=P+Q\dfrac vR+R\dfrac{v^2}{R^2}
v'=PR+\left(Q+\dfrac{R'}R\right)v+v^2

Next, setting v=\dfrac{u'}u, so that v'=\dfrac{uu''-(u')^2}{u^2}, allows you to write this as a linear second-order equation. You have

\dfrac{uu''-(u')^2}{u^2}=PR+\left(Q+\dfrac{R'}R\right)\dfrac{u'}u+\dfrac{(u')^2}{u^2}
u''-\left(Q+\dfrac{R'}R\right)u'+PRu=0
u''+Su'+Tu=0

where S=-\left(Q+\dfrac{R'}R\right) and T=PR.
3 0
3 years ago
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