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4 years ago

Convert 10,000 m into kmO1 km0.1 km100 km10 km

Physics

1 answer:

MissTica4 years ago

6 0

Answer:

10 km

Explanation:

1 km = 1000 m

1 m = 1× 10 -³

There for

10,000 m = 10,000×1× 10 -³

= 10 km

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A clothes dryer in a home draws a current of 10 amps when connected on a special 220-volts household circuit.what is the resista

aliya0001 [1]

Answer:

22Ω

Explanation:

if V ⇒ voltage

I ⇒ current

R ⇒ resistance

V = IR

220 = 10 x R

220 / 10 = R

22 = R

8 0

2 years ago

Suppose that there are N=108 two-state systems, each with energy difference E=6 × 10-21 J between the two states. The environmen

kati45 [8]

Answer:

The value of $\dfrac{dU}{dM}$ is $6\times10^{-29}\ J/unit$ .

Explanation:

Given that,

Number $N=10^{8}$

Energy difference = 6\times10^{-21}\ J[/tex]

Temperature T =300 K

We need to calculate the value of $\dfrac{dU}{dM}$

We know that,

$\dfrac{dU}{dM}=\dfrac{energy\ difference}{Change\ in\ number\ of\ system}$

$\dfrac{dU}{dM}=\dfrac{6\times10^{-21}}{10^{8}}$

$\dfrac{dU}{dM}=6\times10^{-29}\ J/unit$

Hence, The value of $\dfrac{dU}{dM}$ is $6\times10^{-29}\ J/unit$ .

5 0

4 years ago

How many seconds are in 28 hours?

kumpel [21]

Answer:

1680 seconds

Explanation:

$28 hrs * \frac{60 s}{1 hr} =1680s$

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2 years ago

A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the

Margaret [11]

Hi there!

$\boxed{\omega = 0.38 rad/sec}$

We can use the conservation of angular momentum to solve.

$\large\boxed{L_i = L_f}$

Recall the equation for angular momentum:

$L = I\omega$

We can begin by writing out the scenario as a conservation of angular momentum:

$I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)$

$I_m$ = moment of inertia of the merry-go-round (kgm²)

$\omega_m$ = angular velocity of merry go round (rad/sec)

$\omega_f$ = final angular velocity of COMBINED objects (rad/sec)

$I_b$ = moment of inertia of boy (kgm²)

$\omega_b$ = angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

$I = MR^2$

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

$\omega = \frac{v}{r}$

$L_b = MR^2(\frac{v}{R}) = MRv$

Plug in the given values:

$L_b = (20)(3)(5) = 300 kgm^2/s$

Now, we must solve for the boy's moment of inertia:

$I = MR^2\\I = 20(3^2) = 180 kgm^2$

Use the above equation for conservation of momentum:

$600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}$

8 0

3 years ago

You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.

Rudiy27

Answer:

The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region

Explanation:

A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.

7 0

4 years ago

Convert 10,000 m into kmO1 km0.1 km100 km10 km​

Convert 10,000 m into kmO1 km0.1 km100 km10 km