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vodka [1.7K]
2 years ago
6

A building under construction requires building materials to be raised to theupper floors by cranes or elevators. An amount of c

ement is lifted 76.2 m by acrane, which exerts a force on the cement that is slightly larger than the weightof the cement. If the network done on the cement is 1.31 × 103 J, what is themagnitude of the net force exerted on the cement?
Physics
1 answer:
gizmo_the_mogwai [7]2 years ago
4 0

Answer:

<h3>17.19N</h3>

Explanation:

Work = 1.31 × 10³ = 1310

F = W/D = 1310/76.2

≈ 17.19N

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What is the energy of a photon released by an electron going from the first excited energy (n=2) level to ground state (n=1). No
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Answer:    

E= 10.2 ev

Wavelength= 1.21 \times 10^{-7} \ m

Frequency =2.479 \times 10^{15} \ s^{-1}

Explanation:

It is given that energy in first exited state (n=2) , E_2= -3.4 ev

Also , it is given than energy in ground state (n=1) , E_1= -13.6 ev.

We know energy of photon released is difference of the final and initial level of electron.

Energy of photon released,  E=E_{final}-E_{initial}

Therefore, E=(-3.4) - (-13.6)\ ev=10.2\ ev.

To convert energy from ev(electron volt) into joule we need to multiply energy in ev by charge of electron which is ( 1.6 \times 10^{-19} )

Therefore, E_{joule} = E_{ev}\times 1.6 \times 10^{-19} \ joules

Now , we know that photon is an quantum of light . Therefore, speed of photon in vaccum is equal to speed of light which is , c=3\times 10^8\ m/s.

Now, by energy-wavelength relation,

E_{joule}=\dfrac{h\times c}{\lambda}

where , h=6.626\times 10^{-34}\ joule-second

Now, putting values of h ,c and E in above equation .

10.2 \times 1.6\times 10^{-19}=\dfrac{6.626\times10^{-34} \times 3 \times 10^8}{\lambda}

\lambda=\dfrac{{6.626\times10^{-34} \times 3 \times 10^8}}{10.2 \times 1.6\times 10^{-19}}

\lambda=1.21 \times 10^{-7}\ m

We know, c=\lambda\times frequency

Therefore, frequency=\dfrac{c}{\lambda}= \dfrac{3\times 10^8}{1.21\times 10^-7} \ s^{-1}=2.479\times 10^{15} \ s^{-1}

Hence, this is the required solution.

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