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3 years ago

You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.

Physics

1 answer:

Rudiy273 years ago

7 0

Answer:

The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region

Explanation:

A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.

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Someone help me please I don’t even know if that’s physics or not I just need help

WARRIOR [948]

Answer:

1. the robber carrying the metal safe will hurt more because the metal safe is heavier, so the heavier will be the force on the opposite direction from the one he was running when he hit the wall

2. ???

Explanation:

1. 3rd newton law: "If two bodies exert forces on each other, these forces are equal in magnitude and opposite in direction"

2. I don't know

4 0

2 years ago

A jetliner leaves san francisco for new york, 4600 km away. with a strong tailwind, its speed is 1100 km/hr. at the same time, a

Troyanec [42]

First, make an illustration of the problem. In reality, the direction traveled by the planes is not linear. Strictly speaking, it should curve out following the shape of the sphere. But I suppose, we could do away with that because we are given with the quantity for distances. I'm just showing a guide to see where the planes would meet.

So, we know that the total distance is 4,600 km. It would consequently mean that x and y would equal to 4,600. The distances x and y could be determined by multiplying their respective speeds to the time. Since they meet at the same time, let's denote it as t.

1,100t + 700t = 4,600
Solving for t,
1,800t = 4600
t = 4600/1800
t = 2.556 hours

So, we know that the two planes would meet after 2.56 hours from the time they leave the airports. Next, we have to know where they meet exactly.

1,100(2.556) = 2,812 km
700(2.556) = 1,788 km

Therefore, they meet at approximately 2,812 km from San Francisco airport, or 1,788 km from New York airport after 2.56 hours since they left their respective ports.

8 0

2 years ago

If the radius of the earth was suddenly tripled and its mass doubled, the surface gravitational acceleration would become: A) 9.

Mars2501 [29]

Answer:

B) 2.18 m/s²

Explanation:

M = Original mass of earth

R = Original radius of earth

g = original acceleration due to gravity of earth = 9.8 m/s²

M' = New mass of earth = 2 M

R' = New radius of earth = 3 R

g = original acceleration due to gravity of earth = 9.8 m/s²

Original acceleration due to gravity of earth is given as

$g=\frac{GM}{R^{2}}$

$9.8 =\frac{GM}{R^{2}}$ eq-1

g' = new acceleration due to gravity of earth

New acceleration due to gravity of earth is given as

$g' =\frac{GM'}{R'^{2}}$

$g' =\frac{G(2M)}{(3R)^{2}}$

$g'=\left ( \frac{2}{9} \right )\frac{GM}{R^{2}}$

Using eq-1

$g'=\left ( \frac{2}{9} \right )(9.8)$

g' = 2.18 m/s²

8 0

3 years ago

Which contains the most moles: 10 g of hydrogen gas, 100 g of carbon, or 50 g of lead?

Stolb23 [73]

Answer:

Carbon

Explanation:

We know that

Number of moles = mass/molecular mass

Hydrogen: given as H2 with 10g an atomic number of 1 so MW( 1x 2= 2)

Number of moles = Weight/MW

= 10/2

= 5

Carbon: atomic number 12 C and mass 100

Number of moles = Weight/MW

= 100/12

= 8.33

Lead: atomic num 207 and mW 207 pb

Number of moles = Weight/MW

= 50/207

= 0.241

Therefore Carbon has the most moles.

5 0

3 years ago

Billy drops a ball from a height of 1 m. The ball bounces back to a height of 0.8 m, then

Andreas93 [3]

Answer:

The displacement is $\Delta H = - 1 \ m$

The distance is $D = 4 \ m$

Explanation:

From the question we are told that

The height from which the ball is dropped is $h = 1 \ m$

The height attained at the first bounce is $h_1 = 0.8 \ m$

The height attained at the second bounce is $h_2 = 0.5 \ m$

The height attained at the third bounce is $h_3 = 0.2 \ m$

Note : When calculating displacement we consider the direction of motion

Generally given that upward is positive the total displacement of the ball is mathematically represented as

$\Delta H = (0 - h ) + ( h_1 - h_1 ) + (h_2 - h_2 )+ (h_3 - h_3)$

Here the 0 show that there was no bounce back to the point where Billy released the ball

$\Delta H = (0 - 1 ) + ( 0.8- 0.8 ) + (0.5 - 0.5 )+ (0.2 - 0.2)$

=> $\Delta H = - 1 \ m$

Generally the distance covered by the ball is mathematically represented as

$D = h + 2h_2 + 2h_3 + 2h_3$

The 2 shows that the ball traveled the height two times

$D = 1 + 2* 0.8 + 2* 0.5 + 2* 0.2$

=> $D = 4 \ m$

5 0

3 years ago