I have 7 kinds of lunch meat and five kind of bread how many sanwiches can i make using 1 meat and one bread
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Answer:
72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they have a laptop, or they do not. The probability of a student having a laptop is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
A study indicates that 62% of students have have a laptop.
This means that
You randomly sample 8 students.
This means that
Find the probability that between 4 and 6 (including endpoints) have a laptop.
72.69% probability that between 4 and 6 (including endpoints) have a laptop.
Well, you have to be given an interval. That is not an interval.
You should be given something like
If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3
You should be given something like
If you add those fractions up you'll just get a point on the number line.
Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3
You'll end up with a point on 2/3