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Lady bird [3.3K]
3 years ago
15

6x - 12 = 2 (3x - 9) + 6

Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

6x + -12 = 3x + 9

Reorder the terms:

-12 + 6x = 3x + 9

Reorder the terms:

-12 + 6x = 9 + 3x

Solving

-12 + 6x = 9 + 3x

Step-by-step explanation:

12 + 6x = 9 + 3x

-12 + 6x = 9 + 3x

-12 + 6x + -3x = 9 + 3x + -3x

6x + -3x = 3x

-12 + 3x = 9 + 3x + -3x

3x + -3x = 0

-12 + 3x = 9 + 0

-12 + 3x = 9

-12 + 12 + 3x = 9 + 12

-12 + 12 = 0

0 + 3x = 9 + 12

3x = 9 + 12

9 + 12 = 21

3x = 21

Divide each side by 3

x = 7

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The equation that solve for x is as follows;

70 + 60 + x = 180

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The equation that can be used to find the measure of angle x can be found as follows:

60 + 70 + y = 180

Therefore,

130 + y = 180

subtract 130 from both sides

130 - 130 + y = 180 - 130

y = 50°

70 + 60 + x = 180

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x = 180 - 130

x = 50°

x and y are  vertically opposite angles.

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Mr. Martin’s math test which is worth 100 points has 29questions. Each problem is worth 2points or 5 points. X represents number
adell [148]

Answer:there are 14 5point problems and 15 2point problems on the test.

Step-by-step explanation:

x represents number of 5 point questions and y represents questions worth 2 points.

The total number of questions in the test is 29. It means that

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x = 29 - y

Mr. Martin’s math test is worth 100 points. It means that

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1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
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1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

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To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

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\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

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