Answer:
Yea it does
Step-by-step explanation:
T chart but thats all i can think of
Area of a circle = pi*r^2.
Here, A = 380.13 mi. Unfortunately, "mi" is NOT a unit of area.
So I will assume that the problem should read A = 380.13 sq. miles.
380.12 mi^2
Thus, 380.13 mi^2 = 3.14*r^2, and r^2 = ------------------- 121.057 mi^2
3.14
The radius is the sqrt of 121.057 mi^2: 11.00 miles.
The diam. is twice that, or d = 22.00 miles.
( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
