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klasskru [66]
3 years ago
5

When 5 adult join a group of y diner the ratio of the number of adults to children in the restaurant became 3:5. Express the num

ber of children in terms of y
Mathematics
1 answer:
faltersainse [42]3 years ago
4 0
When 5 adults joined the group of y: y+5

The ratio of the number of adults to children became 3:5, so the number of children to total diner should be 5:8. (8=3+5)

So the number of children would be (5/8)*(y+5) = (5y+25)/8


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Two students in your class, Hunter and Maggie, are disputing a function. Hunter says that for the function, between x = −2 and x
dangina [55]
So basically, if it goes up then back down to the same level, the change is 0 since it is like, running 100 feet west, then running 100 feet east, you are at your original spot, your positino did not change

maggie is explaing what hunter is saying


7 0
3 years ago
Read 2 more answers
Which expression gives the distance between the points (4,6) and (7,-3)
defon

Answer:

D = 9.4868

Step-by-step explanation:

The expression is the following

D = √((x2-x1)^2+(y2-y1)^2)

Where

(x1,y1) = (4,6)

(x2,y2) = (7,-3)

D = √((7-4)^2+(-3-6)^2)

D = √((3)^2+(-9)^2)

D = √(9+81)

D = √(90)

D = 9.4868

6 0
4 years ago
Read 2 more answers
Which number produces an irrational number when added to 1/3 ?
gavmur [86]
It is B, 100 percent sure
7 0
2 years ago
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 


go to right side now

4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side
4 0
3 years ago
If cosA=2/5, find the value of 4+4 tan^2A
Andrew [12]
The first equation is given to determine A.

cos A = 2/5
A = cos⁻¹(2/5) = 66.42°

Now that we know A, we use this value to the second equation.

4 + 4tan²A = 4 +24.996 4tan²(66.42°) = 24.996 ≈ <em>25</em>
7 0
3 years ago
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