The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
Answer:
1. ∠ABD = 20°.
2. Arc AB = 140°.
3. Arc AD = 40°.
Step-by-step explanation:
Given information: ∠ADB = 70°. BD is diameter.
According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.
By Central angle theorem,
Using angle sum of property in triangle ADB we get,
.
Draw a line segment AO.
In triangle AOD, AO=OD, so
Using angle sum property in triangle AOD,
Therefore length of arc AD is 40°.
The angle AOD and AOB are supplementary angles.
Therefore length of arc AB is 140°.
Answer:
To answer the question, more information is needed. For instance, if you know the amount of trail mix in each bag. But, to find an average, you first add up all the numbers (the amount of trail mix in each bag). Then divide the sum by the number of numbers (the amount of bags).
Step-by-step explanation:
