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fredd [130]
3 years ago
13

PLEASE HELP ME PLSSSS I WILL MARK YOUR BRAINLIEST Kalie puts 6 stickers on her desk. Each sticker is 1/2 centimeters wide by 3/5

centimeters long. What was the total area, in square centimeters, of all Kalie’s stickers?
Mathematics
1 answer:
Damm [24]3 years ago
8 0

Answer:

Total area: 9/5 square cm, or in decimal form 1.8 square cm

Step-by-step explanation:

Notice that each sticker is 1/2 cm by 3/5 cm, therefore they area is 1/2 times 3/5 = 3/10  square cm.

since she uses 6 of them, we need to multiply the area of each by 6 in order to get the total area:

6 times 3/10 = 18/10 square cm = 9/5 square cm or in decimal form 1.8 square cm

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Answer:

48.6

Step-by-step explanation:

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Which is the odd one out<br> 180<br> 45<br> 79<br> 270 please help me!
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Answer:

79

Step-by-step explanation:  2 4 6 8 are even numbers 1 3 5 7 9 are odds and 79 it the only one that is a odd number

4 0
2 years ago
Compute the surface area of the portion of the sphere with center the origin and radius 4 that lies inside the cylinder x^2+y^2=
Tom [10]

Answer:

16π

Step-by-step explanation:

Given that:

The sphere of the radius = x^2 + y^2 +z^2 = 4^2

z^2 = 16 -x^2 -y^2

z = \sqrt{16-x^2-y^2}

The partial derivatives of Z_x = \dfrac{-2x}{2 \sqrt{16-x^2 -y^2}}

Z_x = \dfrac{-x}{\sqrt{16-x^2 -y^2}}

Similarly;

Z_y = \dfrac{-y}{\sqrt{16-x^2 -y^2}}

∴

dS = \sqrt{1 + Z_x^2 +Z_y^2} \ \ . dA

=\sqrt{1 + \dfrac{x^2}{16-x^2-y^2} + \dfrac{y^2}{16-x^2-y^2} }\ \ .dA

=\sqrt{ \dfrac{16}{16-x^2-y^2}  }\ \ .dA

=\dfrac{4}{\sqrt{ 16-x^2-y^2}  }\ \ .dA

Now; the region R = x² + y² = 12

Let;

x = rcosθ = x; x varies from 0 to 2π

y = rsinθ = y; y varies from 0 to \sqrt{12}

dA = rdrdθ

∴

The surface area S = \int \limits _R \int \ dS

=  \int \limits _R\int  \ \dfrac{4}{\sqrt{ 16-x^2 -y^2} } \ dA

= \int \limits^{2 \pi}_{0} } \int^{\sqrt{12}}_{0} \dfrac{4}{\sqrt{16-r^2}} \  \ rdrd \theta

= 2 \pi \int^{\sqrt{12}}_{0} \ \dfrac{4r}{\sqrt{16-r^2}}\ dr

= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}

= 8\pi ( - \sqrt{4} + \sqrt{16})

= 8π ( -2 + 4)

= 8π(2)

= 16π

4 0
3 years ago
How can you tell whether a table is linear or exponential
Bingel [31]
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7 0
3 years ago
Helppppp plzzzzzzzz<br> No links please and thank you .
kow [346]

Answer:

for the first picture: 2.16

Step-by-step explanation:

12% of 18 is 2.16:

-convert 12 % to a decimal so 0.12 times 18

also, 12 % percent is 0.12 as a decimal because you move the decimal 2 places to the left to get .12

- multiply 0.12 times 18 to get 2.16 as the answer

I hope this helped for the first pic!

4 0
2 years ago
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