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Vaselesa [24]
3 years ago
9

What is the value of X? (8y+12) (7x+4)​

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

The value of x is -\frac{4}{7}

Step by step explanation:

In the question we are given a product that contains two unknown variables, i.e. x and y. To solve for x we shall first compute the product between the two brackets. I will show each step in full detail, in order to understand the product computation of such cases (i.e. distributive property).

(8y+12)(7x+4)=0\\\\8y*7x+4*8y+12*7x+12*4=0\\\\56xy+32y+84x+48=0\\\\

Up to this point we have computed the product and now we have all our terms. Since we want to find the value of x we will gather together all terms that contain x (even if they also contain y) and then do some manipulations and simplifications to obtain our result, as follow:

56xy+32y+84x+48=0\\\\56xy+84x=-32y-48\\\\14x(4y+6)=-8(4y+6)

Now we see that on both sides of the equality we have a common term of   (4y+6), which we can cancel out from both sides, which leaves us with:

14x=-8\\\\x=-\frac{8}{14}\\\\ x=-\frac{4}{7}

Thus the value of x is -\frac{4}{7}.

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