<u>Answer:</u> The initial concentration of
are 0.0192 M and 0.0192 M respectively.
<u>Explanation:</u>
We are given:
Equilibrium concentration of HI = 0.030 M
Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)
For the given chemical equation:
![H_2+I_2\rightleftharpoons 2HI](https://tex.z-dn.net/?f=H_2%2BI_2%5Crightleftharpoons%202HI)
<u>Initial:</u> x x -
<u>At eqllm:</u> x-c x-c 2c
Calculating the value of 'c'
![2c=0.030\\\\c=\frac{0.030}{2}=0.015M](https://tex.z-dn.net/?f=2c%3D0.030%5C%5C%5C%5Cc%3D%5Cfrac%7B0.030%7D%7B2%7D%3D0.015M)
The expression of
for above reaction follows:
![K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D)
We are given:
![K_{eq}=50.2](https://tex.z-dn.net/?f=K_%7Beq%7D%3D50.2)
![[H_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BH_2%5D%3D%28x-c%29%3D%28x-0.015%29)
![[I_2]=(x-c)=(x-0.015)](https://tex.z-dn.net/?f=%5BI_2%5D%3D%28x-c%29%3D%28x-0.015%29)
Putting values in above equation, we get:
![50.2=\frac{(0.030)^2}{(x-0.015)\times (x-0.015)}\\\\x=0.0108,0.0192](https://tex.z-dn.net/?f=50.2%3D%5Cfrac%7B%280.030%29%5E2%7D%7B%28x-0.015%29%5Ctimes%20%28x-0.015%29%7D%5C%5C%5C%5Cx%3D0.0108%2C0.0192)
Neglecting the value of x = 0.0108 M, because the initial concentration cannot be less than the equilibrium concentration.
x = 0.0192 M
Hence, the initial concentration of
are 0.0192 M and 0.0192 M respectively.
The thing that they have in common is that they are all non metals
Answer:
beliefs, thoughts, ideas, and emotions
Explanation:
freedom of expression guarantees the freedom to express oneself without government censorship or media censorship.
Answer:
Because of Hydrogen Bonding!
Its D for plato.
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