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Evgesh-ka [11]
3 years ago
6

Can I have help on this?

Chemistry
1 answer:
zhuklara [117]3 years ago
8 0

Answer:

H20

Explanation:

The acronym (I) used means it is liquid.

hope this helps

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4 years ago
Which of the following statements about natural resources is correct
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Answer:

The right choice is "wind power requires a lot of space and depends on local weather patterns "

Explanation:

  1. solar power produces harmful chemicals
  • it is incorrect because solar power doesn't produce any chemicals

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So the right choice is "wind power requires a lot of space and depends on local weather patterns "

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3 years ago
A folded rock can wear away, allowing new layers to be laid down on much older rocks. The meeting of these two rock layer create
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3 years ago
A chemistry graduate student is given 125.mL of a 0.20M acetic acid HCH3CO2 solution. Acetic acid is a weak acid with =Ka×1.810−
Over [174]

Answer : The mass of sodium acetate is, 1.097 grams.

Explanation : Given,

The dissociation constant for acetic acid = K_a=1.8\times 10^{-5}

Concentration of acetic acid (weak acid)= 0.20 M

volume of solution = 125. mL

pH = 4.47

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.8\times 10^{-5})

pK_a=5-\log (1.8)

pK_a=4.74

Now we have to calculate the concentration of sodium acetate (conjugate base or salt).

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

4.47=4.74+\log (\frac{[Salt]}{0.20})

[Salt]=0.107M

Now we have to calculate the mass of sodium acetate.

\text{Concentration}=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{\text{Molar mass of }NaCH_3CO_2\times \text{Volume of solution (in mL)}}

0.107M=\frac{\text{Mass of }NaCH_3CO_2\times 1000}{82g/mol\times 125mL}

\text{Mass of }NaCH_3CO_2=1.097g

Therefore, the mass of sodium acetate is, 1.097 grams.

6 0
4 years ago
What is the empirical formula for butane, C4H10
pochemuha
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