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4 years ago

How do I find the radius of a circle

Mathematics

2 answers:

katovenus [111]4 years ago

6 0

Answer:

Step-by-step explanation:

Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet. You can also use the circumference and radius equation.

saul85 [17]4 years ago

4 0

Answer:

in the center lol idk

Step-by-step explanation:

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I have 12 ones, and I am between 20 and 30. Who am I ?

viktelen [127]

Factorize the number 24.

24 = 2 × 12

Note that 12 is one of the factors of 24.

Hence, 24 is the number that lies between 20 and 30 and has 12 ones, as one of its factors.

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1 year ago

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What is 380 increased by 18%

Triss [41]

First you divide 380 by 100 to get what 1% is, (3.8) and then you multiply by 18 to give you 18%. The answer is 68.4, so add that to 380 and you'll have the final answer of 448.4.

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4 years ago

What is the total area of the shaded triangles?

frozen [14]

Check the picture below.

$\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}~~
\begin{cases}
s=length~of\\
\qquad a~side\\
------\\
s=\frac{s}{3}
\end{cases}\implies A=\cfrac{\left( \frac{s}{3} \right)^2\sqrt{3}}{4}
\\\\\\
A=\cfrac{\frac{s^2\sqrt{3}}{3^2}}{4}\implies A=\cfrac{s^2\sqrt{3}}{4\cdot 3^2}\implies A=\cfrac{s^2\sqrt{3}}{36}
\\\\\\
\textit{and since there are 3 triangles shaded with that area}
\\\\\\
\textit{shaded area}\implies 3\left( \cfrac{s^2\sqrt{3}}{36} \right)\implies \cfrac{s^2\sqrt{3}}{12}$

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4 years ago

A piece of wire of length 5050 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

$A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}$

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

$A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}$

The total combined area of the square and circles is

$\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

$A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0$

$\frac{x}{2\pi} - \frac{5050 - x}{8} = 0$

Multiple both sides by 8π and we have

$4x - 5050\pi + x\pi = 0$

$x(4 + \pi) = 5050\pi$

$x = \frac{5050\pi}{4 + \pi} = 2221.5$

At x = 2221.5:

$A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$ = 392720 + 500026 = 892746 [/tex]

At x = 0, $A = 5050^2/16 = 1593906$

At x = 5050, $A = \frac{5050^2}{4\pi} = 2029424$

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

3 0

3 years ago