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4 years ago

21/84 in simplest form

Mathematics

2 answers:

ipn [44]4 years ago

5 0

Divide the numerator and denominator by 21:

21 / 21 = 1
84 / 21 = 4

So 21/84 is equal to 1/4.

Inessa05 [86]4 years ago

5 0

21/84

21 divided by 3 = 7
84 divided by 3 = 28

28 divided by 7 = 1/4

1/4 is your answer

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6 less than the product of 4 and a number n is -12. What is the number?

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Step-by-step explanation:

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3 years ago

Which phrase could be represented by this expression?

malfutka [58]

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eight more than a fifth of a number

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eight more than a fifth of a number

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3 years ago

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Step-by-step explanation:

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3 years ago

C) Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tu

Dmitry_Shevchenko [17]

$\displaystyle\\|\Omega|=\binom{15}{3}=\dfrac{15!}{3!12!}=\dfrac{13\cdot14\cdot15}{2\cdot3}=455$

$\displaystyle\\|A|=\binom{10}{3}=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{2\cdot3}=120\\\\P(A)=\dfrac{120}{455}=\dfrac{24}{91}\approx26.4\%$

$\displaystyle\\|A|=\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10\\\\P(A)=\dfrac{10}{455}=\dfrac{2}{91}\approx2.2\%$

$\displaystyle\\|A|=\binom{10}{2}\cdot5=\dfrac{10!}{2!8!}\cdot5=\dfrac{9\cdot10}{2}\cdot5=225\\\\P(A)=\dfrac{225}{455}=\dfrac{45}{91}\approx49.5\%$

$A$ - at least one is spoilt

$A'$ - none is spoilt

$P(A)=1-P(A')$

We calculated $P(A')$ in a).

Therefore

$P(A)=1-\dfrac{24}{91}=\dfrac{67}{91}\approx73.6\%$

7 0

2 years ago