Hello :
<span>8(j-4)=2(4j-16)
</span><span>2(4j-16)= 2(4(j-4))=8(j-4)
</span>8(j-4)= 8(j-4)....(identity : infinty solutions)
Answer:
r = -6, -1
Step-by-step explanation:
r^2 + 7r+6 =0
Factor
What 2 numbers multiply to 6 and add to 7
6*1 =6
6+1 =7
(r+6) (r+1) =0
Using the zero product property
r+6 =0 r+1 =0
r = -6 r=-1
Answer:
10:12:15
Step-by-step explanation:
a/b=5/6
b/c=4/5
thus
c/b=5/4
LCM of 4 and 6=12
5/6=10/12
5/4=15/12
b is the 12 in both
thus ratio between a:b:c is 10:12:15
i can reply in comments if more explanation is needed
Answer:
B = -6
Step-by-step explanation:
7b + 12 = 5b
12 = -2b
-6 = b
Hope this helps. Pls give brainliest.
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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