Answer:
a) x = 1 + t
y = 3 - t
z = 8 +2t
b) In XY plane (-3,-1,0)
In YZ plane (0, 4, 6)
In XZ plane ( 4,0,14)
Step-by-step explanation:
The equation of plane is given as
x -y +2z = 5
a)
COMPARE THE ABOVE EQUATION with Ax+ By +Cz = d
A = 1, B = -1. C = 2
N = (1,3,8) {GIVEN POINT]
the parametric eqn. of line P(Xo , Yo, Zo) and prependicular plan Ax+ By+ Cz = d is given as
X = Xo+ At
Y = Yo + Bt
Z=Zo + Ct
x = 1 + t
y = 3 - t
z = 8 +2t
b) Line intersecting XY plane if z equal to zero i.e
0 = 8 + 2t
t =-4
for t = -4
x = -3, y = -1, z = 0
In YZ plane, x = 0
t = -1
interesting point will be
(0, 4, 6)
In XZ plane, Y = 0
t = 3
interesting point will be
(4, 0, 14)
