<span>Simplifying
x4 = 16
Solving
x4 = 16
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Simplifying
x4 = 16
Reorder the terms:
-16 + x4 = 16 + -16
Combine like terms: 16 + -16 = 0
-16 + x4 = 0
Factor a difference between two squares.
(4 + x2)(-4 + x2) = 0
Factor a difference between two squares.
(4 + x2)((2 + x)(-2 + x)) = 0
Subproblem 1
Set the factor '(4 + x2)' equal to zero and attempt to solve:
Simplifying
4 + x2 = 0
Solving
4 + x2 = 0
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation.
4 + -4 + x2 = 0 + -4
Combine like terms: 4 + -4 = 0
0 + x2 = 0 + -4
x2 = 0 + -4
Combine like terms: 0 + -4 = -4
x2 = -4
Simplifying
x2 = -4
The solution to this equation could not be determined.
This subproblem is being ignored because a solution could not be determined.
Subproblem 2
Set the factor '(2 + x)' equal to zero and attempt to solve:
Simplifying
2 + x = 0
Solving
2 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2
Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2
Combine like terms: 0 + -2 = -2
x = -2
Simplifying
x = -2
Sub-problem 3
Set the factor '(-2 + x)' equal to zero and attempt to solve:
Simplifying
-2 + x = 0
Solving
-2 + x = 0
Move all terms containing x to the left, all other terms to the right.
Add '2' to each side of the equation.
-2 + 2 + x = 0 + 2
Combine like terms: -2 + 2 = 0
0 + x = 0 + 2
x = 0 + 2
Combine like terms: 0 + 2 = 2
x = 2
Simplifying
x = 2Solutionx = {-2, 2}</span>
Answer:
i'm guessing a positive test result
Step-by-step explanation:
Answer:
m^2+5m+25/4
perfect square trinomial^^
Answer:
8 days
Step-by-step explanation:
On day 8, Isabella will save 256 nickels, bringing her total to 510.
_____
The number of nickels saved on day n is 2^n. The total is 2^(n+1)-2.
_____
The above can be written down from your knowledge of binary sequences. If you want a more formal development, read on.
__
The number of nickels saved on day n is a geometric sequence with first term 2 and common ratio 2. The n-th term of the sequence is ...
an = a1·r^(n-1) = 2·2^(n-1) = 2^n
The sum of n terms of the sequence is ...
S = a1(r^n -1)/(r -1) = 2(2^n -1)/(2-1)
S = 2^(n+1) -2
__
We want S > 500, so ...
500 < 2^(n+1) -2
502 < 2^(n+1)
251 < 2^n
log(251) < n·log(2)
n > log(251)/log(2)
n > 7.97 . . . . . . . . 8 days or more to save more than 500 nickels
Answer:
the answer is 5
Step-by-step explanation:
because 5+3 is 8 and 3+0 is 3 so you need 5 so it can be equal.
hoped i helped
