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Lerok [7]
3 years ago
13

What key feature on a graph are you finding when you find the solution

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
3 0
Ty ty a few years ago and he ieoorororowo the old school in class and I didn’t wanna see him in school today lol I think he did a little bit of the one in the one that
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If you have 120 feet of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest are
Tems11 [23]
The area of rectangular is  A= length x width
 
  120 feet of fancing = ---------------------------------- (the above line)


        !-----------------------------------------!                                     
        !                                                   !
     x !   the enclosed area                 ! x
        !                                                   !
        !---------------------------------------- !
                          120 -(x+x)
so the area is  A = (120-2x) (x)= 120x-2x²



4 0
3 years ago
Jaylin has $50 in her fun account she deposit $ 10 per month into the account but $ 6 per month is deducted to pay for a streami
NNADVOKAT [17]

Answer:

16 per month

Step-by-step explanation:

you add the 10 and 6 together making it 16 total a month

6 0
3 years ago
A) Work out 4 1/7 + 1 1/2​
Vesnalui [34]

Answer:

135/14

9 9/14

Step-by-step explanation:

29/7+11/2

4 0
3 years ago
Read 2 more answers
10. Determine whether or not, vectors ui(1,-2, 0, 3), u2 = (2, 3,0,-1), u3 = (3,9,-4,-2) e R is a linear combination of the (2,-
vodka [1.7K]

If (2, -1, 2, 1) is a linear combination of the three given vectors, then there should exist c_1,c_2,c_3 such that

(2,-1,2,1)=c_1(1,-2,0,3)+c_2(2,3,0,-1)+c_3(3,9,-4,-2)

or equivalently, there should exist a solution to the system

\begin{cases}c_1+2c_2+3c_3=2\\-2c_1+3c_2+9c_3=-1\\-4c_3=2\\3c_1-c_2-2c_3=1\end{cases}

Right away we get c_3=-\dfrac12, so the system reduces to

\begin{cases}c_1+2c_2=\dfrac72\\\\-2c_1+3c_2=\dfrac72\\\\3c_1-c_2=0\end{cases}

Notice that the first equation is the sum of the latter two. The third equation gives us

3c_1-c_2=0\implies 3c_1=c_2

so that in the second equation,

-2c_1+3c_2=\dfrac72\implies7c_1=\dfrac72\implies c_1=\dfrac12

which in turn gives

3c_1=c_2\implies c_2=\dfrac32

and hence the (2, -1, 2, 1) is a linear combination of the given vectors, with

\boxed{(2,-1,2,1)=\dfrac12(1,-2,0,3)+\dfrac32(2,3,0,-1)-\dfrac12(3,9,-4,-2)}

5 0
4 years ago
I need help on question 1
Alexus [3.1K]
The answer is 15

Hope this helps you
8 0
4 years ago
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