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2 years ago

What key feature on a graph are you finding when you find the solution

1 answer:

3 0

Ty ty a few years ago and he ieoorororowo the old school in class and I didn’t wanna see him in school today lol I think he did a little bit of the one in the one that

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Help plsss thankss

klasskru [66]

Answer:

The coefficient of the quadratic term ,a,determines how wide or narrow the graphs are, and

weather the graph turns upward or downward

Step-by-step explanation:

this is your answer

5 0

1 year ago

A can is 4 inches wide and 8 inches tall. To the nearest whole number, what is the area of a label that wraps around the can if

Yakvenalex [24]

Answer:

The area of a label is $62.8\ in^{2}$

Step-by-step explanation:

we know that

The lateral area of a cylinder (label of the can) is equal to

$LA=2\pi rh$

we have that

A can is 4 inches wide

The diameter of the can is 4 inches

$r=4/2=2\ in$ ----> the radius is half the diameter

$h=8-3=5\ in$ ----> height of the label

substitute in the formula

$LA=2(3.14)(2)(5)=62.8\ in^{2}$

5 0

3 years ago

Find the Volume. help please

Oksana_A [137]

104 1/2ft cubed
To find the volume you would multiply
Length•width•height
So,
(6 1/3)(3)(5 1/2)=104 1/2
So it would be 104 and 1/2 or 104.5

6 0

2 years ago

Given that the triangles are similar how to find x

alexdok [17]

So if they are similar then just try to figure out which two sides correspond to each other from the first and then the second triangle.

See how in the above example I did 20 and 5 not 20 and 14 or 20 and 3.5 because they do not correspond with one another.

Then figure out, is x on the mama or baby shape and either multiply the number received from all proportions or divide.

Multiply : small to big ( # missing on the bigger one )

Divide : big to small ( # missing on the smaller one)

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I hope that helps you out!! Any more questions??

3 0

3 years ago

(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.

masya89 [10]

ANSWER

b.

EXPLANATION

The given polar equation is,

$r = \frac{12}{6 + 4 \cos( \theta) }$

Cross multiply to get,

$r(6 + 4 \cos( \theta) ) = 12$

$6r + 4r\cos( \theta) ) = 12$

Substitute,

$r\cos( \theta) = x$

and

$r = \sqrt{ {x}^{2} + {y}^{2} }$

$6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12$

$3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6$

$3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x$

$9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}$

$9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}$

$5{x}^{2} + 9 {y}^{2} + 16x = 16$

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0

3 years ago