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Vladimir79 [104]
3 years ago
10

3) Asanji's school is selling tickets to the annual dance competition. On the first day of ticket sales the

Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

C) senior citizen ticket 10$, child ticket 11$

Step-by-step explanation:

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mrs. warburton weighs her suitcases ready for holiday.It weighs 7.35kg she takes out shoes that weigh 2.6.How heavy is her suitc
kiruha [24]
So all you need to do is 7.35kg takeaway 2.6kg = 4.75kg

Mrs Warburton's bag now weighs 4.75kg
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Please Hurry). Question: What is the value of x? (Will Mark Brainliest) Please only answer if you know it.​
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111

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Is 1/4 and 3/8 proportional
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Evaluate a+b for a=-17 and b=8
In-s [12.5K]

25

substitute 17 for A

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17+8

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8 0
3 years ago
Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0
3 years ago
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