Answer:
A person can select 3 coins from a box containing 6 different coins in 120 different ways.
Step-by-step explanation:
Total choices = n = 6
no. of selections to be made = r = 3
The order of selection of coins matter so we will use permutation here.
Using the formula of Permutation:
nPr = ![\frac{n!}{(n-r)!}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%21%7D%7B%28n-r%29%21%7D)
We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.
Order of coin is important means that if we select 3 coins in these two orders:
--> nickel - dime - quarter
--> dime - quarter - nickel
They will count as two different cases.
Calculating the no. of ways 3 coins can be selected from 6 coins.
nPr =
= ![\frac{6!}{(6-3)!}](https://tex.z-dn.net/?f=%5Cfrac%7B6%21%7D%7B%286-3%29%21%7D)
nPr = 120
Answer:
of what?
Step-by-step explanation:
Answer:
53/10 > 38/10
Step-by-step explanation:
Answer:
5 tables
Step-by-step explanation:
3 = 24
1 = 24 ÷ 3 = 8
40 chairs = 40 ÷ 8 = 5
Hope this helps!