It would be a a 6 by 5 inch rectangle, since the height is 6in and the width is 5in. Those are what would make up the cross section.
One of the ways to graph this is to use plug in a few x-values and get an idea of the shape. Since the x values keep getting squared, there is an exponential increase on either side of the y-axis. You can see this by plugging in a few values:
When
x=0,f(x)=0
x=1,f(x)=1^2=1
x=2,f(x)=2^2=4
x=3,f(x)=3^2=9
x=4,f(x)=4^2=16
The same holds true for negative x-values to the left of the y-axis since a negative value squared is positive. For example,
x=−1,f(x)=(−1)2=1*−1=1
x=2,f(x)=(−2)2=−2*−2=4
The graph of f(x)=x^2 is called a "Parabola." It looks like this:
Answer: Yes these triangles are similar
Step-by-step explanation:
First lets write down what we know just to make life easier
x=9
TL should be similar to CH
LY should be similar to KH
The angles should be equal due to SAS
So the first thing we know is true is the fact that they have equal angles. Now we have to find out if the sides are similar or if they change by the same ratio to the other. If TL is similar to CH and TL=25 and CH=10 what is the change in size or dilation. Division should do the trick so 25/10=2.5 so TY is greater than CH by a factor of 10. Which means that LY should also be greater than KH by a factor of 2.5. If we are told that x=9 than side LY or 4(9)-1=35 and KH 9+5=14
So side KH is 14 and LY is 35. Now to check if they are similar then KH should be greater by a factor of 2.5. If this is not true than the sides are not similar. 35/2.5=14
Since 35 divided by 2.5 is 14 we can tell both sides TL and LY are greater than KH and CH by a factor of 2.5
Hope this helps.
Answer:
24/t-10
Step-by-step explanation:
So its quotient so 24/t, and minus 10 becuase less than
