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frutty [35]
3 years ago
10

Please help me with this math question!

Mathematics
1 answer:
barxatty [35]3 years ago
6 0
1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>\sqrt[n]{3} =   3^{ \frac{1}{n} }.

The square root of 3 (\sqrt{3}) = 3 to the one-half power (3^{ \frac{1}{2} }).
The 5th root of 3 (\sqrt[5]{3}) = 3 to the one-fifth power (3^{ \frac{1}{5} }).

2) Now use the product of powers exponent rule to simplify:
This rule says a^{m} a^{n} = a^{m+n}&#10;. When two expressions with the same base (a, in this example) are multiplied, you can add their exponents while keeping the same base.

You now have (3^{ \frac{1}{2} })*(3^{ \frac{1}{5} }). These two expressions have the same base, 3. That means you can add their exponents:
(3^{ \frac{1}{2} })(3^{ \frac{1}{5} })\\&#10;= 3^{(\frac{1}{2} + \frac{1}{5}) }\\&#10;= 3^{\frac{7}{10}}

3) You can leave it in the form 3^{\frac{7}{10}} or change it back into a radical \sqrt[10]{3^7}

------

Answer: 3^{\frac{7}{10}} or \sqrt[10]{3^7}
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3 years ago
The discriminant for the equation f(x)=6x^(2)-x+c is 73. What is the value of c?
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