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eduard
2 years ago
6

A company manufactures batteries in batches of 26 and there is a 3% rate of defects. Find the standard deviation for the number

of defects per batch.
Mathematics
1 answer:
LuckyWell [14K]2 years ago
6 0

Answer:

The standard deviation for the number of defects per batch is 0.87.

Step-by-step explanation:

Let <em>X</em> denote the number of defective batteries per batch.

A company manufactures batteries in batches of <em>n</em> = 26.

It is provided that the rate of defects is, <em>p</em> = 0.03.

Each battery is defective independently of the others.

The random variable <em>X</em> follows a binomial distribution.

The standard deviation of a binomial distribution is:

\sigma=\sqrt{np(1-p)}

Compute the standard deviation for the number of defects per batch as follows:

\sigma=\sqrt{np(1-p)}

  =\sqrt{26\times 0.03\times (1-0.03)}\\\\=0.86982757\\\\\approx 0.87

Thus, the standard deviation for the number of defects per batch is 0.87.

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Answer:

1.\frac{9}{5}

2.-11\frac{1}{4}

3.10\frac{1}{8}

4.4\frac{17}{24}

5.-4\frac{7}{12}

Step-by-step explanation:

In order to solve them you just have to multiply them and add them:

3 (\frac{3}{5} )=\frac{15+3}{5}=\frac{18}{5}

-4\frac{1}{2}  (2\frac{1}{2} )=-(\frac{9}{2} )(\frac{5}{2}) =-(\frac{45}{4}) =-11\frac{1}{4}

(-2\frac{1}{4} )(-4\frac{1}{2}) =(-\frac{9}{4}) (-\frac{9}{2} )=-\frac{81}{8} =-10\frac{1}{8}

3\frac{3}{8}+ 4\frac{1}{3}=7\frac{8+9}{24} =7\frac{17}{24}

-2\frac{1}{4} +-2\frac{1}{3}=-4\frac{7}{12}

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2 years ago
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Answer:

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Step-by-step explanation:

First you bring over the added variable. 0.194185, and subtract it from 66. Then you divide your difference by 0.985897. This gives you 66.74715005725

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Solve the system by graphing.
igor_vitrenko [27]

Answer:

Hi There the correct answer is {x,y} = {-1,-10}  

 

System of Linear Equations entered :

  [1]    3x - y = 7

  [2]    4x - 2y = 16

Graphic Representation of the Equations :

   y + 3x = 7        -2y + 4x = 16  

 

 

Solve by Substitution :

// Solve equation [1] for the variable  y  

 

 [1]    y = 3x - 7

// Plug this in for variable  y  in equation [2]

  [2]    4x - 2•(3x-7) = 16

  [2]    -2x = 2

// Solve equation [2] for the variable  x  

  [2]    2x = - 2  

  [2]    x = - 1  

// By now we know this much :

   x = -1

   y = 3x-7

// Use the  x  value to solve for  y  

   y = 3(-1)-7 = -10  

Solution :

{x,y} = {-1,-10}  

Hope it helps!

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