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Reil [10]
4 years ago
12

How many intersections are there of the graphs of the equations below? x + 5y = 6 3x + 30y = 36

Mathematics
2 answers:
leva [86]4 years ago
7 0
D) infinitely many

Hope this helped!
ahrayia [7]4 years ago
4 0

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

x+5y=6\\\\and\\\\3x+30y=36

We need to find that " How many solutions are there ?"

First we compare the coefficients of x and y :

a_1x+b_1y=c_1\\\\and,\\\\a_2x+b_2y=c_2

Now,

\frac{a_2}{a_1}=\frac{b_2}{b_1}=\frac{c_2}{c_1}

Here,

a_1=1,a_2=5,c_1=-6\\\\and\\\\a_2=3,b_2=30,c_2=36

so,  it becomes,

\frac{1}{3}=\frac{5}{30}=\frac{-6}{-36}\\\\\frac{1}{3}\neq \frac{1}{6}=\frac{1}{6}

So, it becomes intersecting lines . So, they have unique solution.

Hence, Option 'B' is correct.

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Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
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Solution : -\frac{3}{4}-\frac{3}{4}i

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=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

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= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

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