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vova2212 [387]
2 years ago
10

Which one of the following symbols means less than

Mathematics
2 answers:
wel2 years ago
7 0

Answer:

< means less than

example: 7 < 10

Step-by-step explanation:

Damm [24]2 years ago
6 0

Answer:

>

Step-by-step explanation:

< this is greater than

= this is equal to

I don't know how else to explain this

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Another question (picture)
ASHA 777 [7]


\left( 16 x^8 y^{-12} \right)^{\frac 1 2} = 16^{\frac 1 2} (x^8)^{\frac 1 2} (y^{-12})^{\frac 1 2} = 4 x^4 y^{-6} = \dfrac{4 x^4}{y^6}


Third choice



8 0
3 years ago
7(y+3)=5y+8<br> Is this <br> A.Solution<br> B.No Solution<br> C. Infinite Solution
faust18 [17]

First, let's use the Distributive Property to make our equation easier to solve. Remember that the Distributive Property says the following:

a(b + c) = ab + ac


Using this, we can multiply the 7 out to the y and 3. This gives us:

7y + 21 = 5y + 8


Now, let's solve for y:

2y + 21 = 8

2y = -13

y = - \dfrac{13}{2}


We can see that there is one solution for this equation because y is equal to one definite value after solving. Thus, our answer is A, one solution.  

3 0
3 years ago
How you do multiply complex numbers ? Example : (9 - 4i) (8 + 6i)
Andrew [12]

You multiply them just as you would multiply any normal polynomials, except there is a special rule. Since we know that i = √-1, the rule is that i² = -1. So, let's multiply:

(9-4i)(8+6i) = 72+54i-32i-24i^2

Let's simplify this:

72+22i+(-24*-1)

72+22i+24 = 96+22i

Therefore, your answer is 96 + 22i.

6 0
3 years ago
Graph the six terms of a finite sequence where a_1 = -3 and r = 1.5
marysya [2.9K]
Here's a graph of those terms.

6 0
3 years ago
T F IfA and B are similar matrices, then AT=BT
muminat

Answer:

Step-by-step explanation:

We know that for two similar matrices A and B exists an invertible matrix P for which

[tex]B = P^{-1} AP[/tex]

∴ B^{T} = (P^{-1})^{T} A^{T} P^{T} \\

Also P^{-1}P = I\\

and (P^{-1})^{T} = (P^{T})^{-1}

∴(P^{-1})^{T}P^{T} = I

so, B^{T} = (P^{-1})^{T} A^{T} P^{T} = (P^{T})^{-1}A^{T} P^{T}\\B^{T} = A^{T} I\\B^{T} = A^{T}

7 0
3 years ago
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