Answer:
7. parallelogram
8. square
9. trapezoid (trapezium) (maybe "acute" - can't see the whole image)
10. rhombus
11. ?
12. rectangle
13. equilateral triangle
14. scalene triangle
15, 16, 17 and 18 are all isosceles triangles as they have 2 sides of equal length
3/5 divided by 1/3 is 9/5 or 1 4/5
Therefore the answer is 1 and 4/5
F(x) = -6(1.02)^x has a y-intercept at f(x) = -6(1.02)^0
f(x) = -6(1)
f(x) = -6
f(x) has a y-intercept at (0, -6)
g(x) has a y-intercept at (0, -3)
Therefore, the y-intercept of f(x) is equal to 2 times the y-intercept of g(x).
Answer:
20.24 cm
Step-by-step explanation:
Here, since the age of the crab is given in months and the regression line was computed using the age in months, we just have to replace the value of the age in the formula to estimate the size.
The formula obtained for the estimated size Y was
Y = 9.1411 + 0.4775X
where X is the age in months
Replacing X with 23.2417, we get
Y = 9.1411 + 0.4775*23.2417 = 20.24 cm
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60