Answer:
- Exact Area = 210.25pi - 210
- Approximate Area = 450.185
The units for the area are in square inches or in^2. The approximate value shown above is when using pi = 3.14
=============================================================
Explanation:
Use the pythagorean theorem to find the length of the hypotenuse
a^2 + b^2 = c^2
20^2 + 21^2 = c^2
400 + 441 = c^2
c^2 = 841
c = sqrt(841)
c = 29
The hypotenuse is 29 inches long. This is the diameter of the circle. Half of that is the radius at r = d/2 = 29/2 = 14.5 inches.
The area of the circle is...
A = pi*r^2
A = pi*(14.5)^2
A = pi*210.25
A = 210.25pi
Which is exact in terms of pi
We'll subtract off the triangular region as this isn't shaded in. The area of the triangle is base*height/2 = 20*21/2 = 420/2 = 210 square inches.
So the shaded region is therefore 210.25pi - 210 square inches
This approximates to 210.25*3.14 - 210 = 450.185 when using the approximation pi = 3.14; use more decimal digits of pi to get a more accurate value.
Answer: a. It is commonly referred to as the arithmetic average.
b. It is algebraically defined (that is, there is an equation you can use to calculate its value).
c. It is easily influenced by extreme scores.
Step-by-step explanation:
The mean is also referred to as the "average" and it is gotten by adding every number and the dividing the value gotten by the number of the numbers used for the calculation.
It should be noted that the mean is algebraically defined and can be easily influenced by extreme scores.
Answer:
The correct answer is p

Step-by-step explanation:
An inequality compares two quantities unlike an equality. An inequality is written with either a greater than ( > ) or lower than ( < ) or greater than equal to ( ) or less than equal to ( ) signs. We solve the above given inequality to find the solutions of the unknown p. An inequality reverses if and only if we we multiply both sides with a negative quantity. Addition or subtraction does not change the sign in the inequality.

First two are scalene last one is isosceles.