Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Hi there
I=prt
P principle 8000
R interest rate 0.095
T time 120/360
I interest earned?
I=8,000×0.095×(120÷360)
I=253.33
Hope it helps
Answer:
62 is the answer.
Step-by-step explanation:
I hope this helps you.
