The distance between is =|9|+|-6|=15.
We can find that

So 2/5 of the AB segment is 6 distance points away from A at point C=0.
4.096 x 10^3
Hope this helps
It would be D because 0.0016*250,000= 400 and 250,000-400=249600
If xy=0 assume that at leas 1 is zero
set it to zero
0=2a^2-16a+32
undistribute 2
0=2(a^2-8a+16)
2*0=0 so assume
a^2-8a+16=0
factor
(a-4)(a-4)=0
set to zero
a-4=0
a=4
when a=4, equation equals zero