First lets see the pythagorean identities
So if we have to solve for sin theta , first we move cos theta to left side and then take square root to both sides, that is
Now we need to check the sign of sin theta
First we have to remember the sign of sin, cos , tan in the quadrants. In first quadrant , all are positive. In second quadrant, only sin and cosine are positive. In third quadrant , only tan and cot are positive and in the last quadrant , only cos and sec are positive.
So if theta is in second quadrant, then we have to positive sign but if theta is in third or fourth quadrant, then we have to use negative sign .
which means
so approximately 0.62% of pandas weight over 250 pounds.
In this case, the vector is passing through a right angle as shown with the little square on the left side. (all right angles equal 90 degrees) so you would simply subtract 64 from 90. (90 - 64 = 26) so x equals 26 degrees.
Answer:
m∠A ≈ 103°
Step-by-step explanation:
Enough information is shown for us to be able to use the Law of Sines to find the angle. That tells us ...
sin(A)/a = sin(C)/c
A = arcsin(a/c·sin(C)) = arcsin(26/6·sin(13°)) = arcsin(0.974788)
A = 77.1° or 102.9°
The claim is that the figure is drawn to scale, so we can assume that A is an obtuse angle:
m∠A ≈ 103°
__
<em>Additional comment</em>
The sum of angles A and B must be 180° -13° = 167°. Since angle A is the largest, it must be more than half this value, or more than 83.5°. That means, we must choose the obtuse angle for A, rather than the acute angle.
