Answer:
V = 288 m^3
Step-by-step explanation:
The formula for volume of a rectangular prism is
V= l*w*h
V = 4*8*9
V = 288 m^3
Answer:
B) \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Step-by-step explanation:
Step 1: First we have to get rid off the roots in the denominator.
To do that, we have to multiply the numerator and the denominator by the conjugate of √5 + √3.
The conjugate of √5 + √3 is √5 - √3.
Now multiply given expression with √5 - √3
(√6 + √11) (√5 - √3)
------------- x -----------
(√5 + √3) (√5 - √3)
Step 2: Multiply the numerators and the denominators.
√6√5 - √6√3 +√11√5 -√11√3
------------------------------------------
(√5)^2 - (√3)^2
Now let's simplify to get the answer.
√30-√18 +√55 - √33
-----------------------------
5 - 3
= √30 -3√2 +√55 [√18 = √9√2 = 3√2]
--------------------------
2
The answer is \sqrt{30} - 3 \sqrt{2} + \sqrt{55} - \sqrt{33} \div 2
Thank you.
Answer:
930.91
Step-by-step explanation:
931 x 99% = 921.69
921.69 x 101% = 930.9069
If two line are perpendicular. The multiply of their slopes are equal to -1.
First line's slope is: -1/2x because if the line equation is form of y=ax+b a is slope.
Let say second line's slope is m
m.-1/2=-1 so m=2
y=ax+b is general form of linear function/equation. (a=slope)
y=2x+b
If this line passes through the point (2,-2),if we write -2 to y and 2 to x, the equation becomes true.
-2=4+b
b=-6
Thus,
y=2x-6 is true answer.
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.