28= 1,2,4,7,14,28,
44=1,2,4,11,22,44,
x+(x+8)+(x+100)=750
3x+108=750
3x=642
x=214
So your numbers are 214, 222 and 314
Given:
6 male professores
9 female professores
5 male teaching assistants
6 female teaching assistants
Sol:.

N (professors)

N(Male)

N(professors and male)

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

N(People to choose from)

Then probablitiy is:

Then the probability is 10/13
First of all, let’s find CB.
sin(45°) = CB : 6sqrt(2)
CB = 6
Now we can find CD
cos(60°) = x : 6
x = 3