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2 years ago

14

How can knowing the greatest common factor and least common multiple help when adding subtracting and multiplying fractions

1 answer:

morpeh [17]2 years ago

3 0

It helps you know what to multiply and the product when you subtracting and adding fractions.

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Find the length of the leg.

g100num [7]

The length of the leg is 5

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2 years ago

Compune o problema dupa ex.110×10-4×7

iVinArrow [24]

110 x 10 - 4 x 7
1,100 - 28
1,072

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3 years ago

Compare the values of each 3 in the number 633,248

ipn [44]

633,248.
The difference of each 3 is that they have different place values.
The 3 on the right side is int he 1000s (thousands) place, and the 3 on the left is in the 10,000s (ten thousands) place. :)

The one in the 10,000s place is 10 times larger than the one in the 1,000s place!

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2 years ago

Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

fomenos

Answer:

$\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1$

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

$\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1$

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is $2a=|4--10|$ .

$\implies 2a=|14|$

$\implies 2a=14$

$\implies a=7$

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is $(\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)$

We need to use the relation $a^2+b^2=c^2$ to find $b^2$ .

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

$c=|6--3|=9$

$\implies 7^2+b^2=9^2$

$\implies b^2=9^2-7^2$

$\implies b^2=81-49$

$\implies b^2=32$

We substitute these values into the standard equation of the hyperbola to obtain:

$\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1$

$\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1$

7 0

2 years ago

2 option question NEED ANSWER NOW PLZ

castortr0y [4]

Do you have a text book?

8 0

3 years ago