Answer:It's easier to divide by a higher number that goes in evenly
Answer:
8, 10
Step-by-step explanation:
Multiplying the equation by the product of the denominators, we have ...
40(x+2) +40x = 9x(x+2)
80x +80 = 9x^2 +18x . . . . eliminate parentheses
9x^2 -62x -80 = 0 . . . . . . put in standard form
9x^2 -72x +10x -80 = 0 . . . prepare to factor by grouping
9x(x -8) +10(x -8) = 0 . . . . . factor pairs of terms
(9x +10)(x -8) = 0
Solutions are ...
x = -10/9 and x = 8
The integers are 8 and 10.
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<em>Comment on the attachment</em>
I find a graphing calculator to be a nice tool for solving these. It finds zeros easily, so writing the equation so it equals zero is a useful first step.
Your pay is described by a piecewise function p(t) where t is hours worked.
![p(t)=\left\{\begin{array}{rcl}7t&\mbox{for}&t\leq40\\10.5t-140&\mbox{for}&t>40\end{array}\right.](https://tex.z-dn.net/?f=p%28t%29%3D%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Brcl%7D7t%26%5Cmbox%7Bfor%7D%26t%5Cleq40%5C%5C10.5t-140%26%5Cmbox%7Bfor%7D%26t%3E40%5Cend%7Barray%7D%5Cright.)
The domain of this function is the number of hours you can work in a week—zero to 168. The range is the set of values p(t) can take on, which we have said is p(0) to p(168). This problem, however, is asking for the range for a typical 40-hour week. That will be p(0) to p(40):
the interval [0, 280].
Answer:
10 .
how i got this calculator
Step-by-step explanation:
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