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koban [17]
3 years ago
13

Consider random samples of size 80 drawn from population A with proportion 0.48 and random samples of size 66 drawn from populat

ion B with proportion 0.13 . (a) Find the standard error of the distribution of differences in sample proportions, . Round your answer for the standard error to three decimal places. standard error
Mathematics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

Standard error = 0.070

Step-by-step explanation:

Formula for the standard error of the distribution of differences in sample proportions is;

σ_(A - B) = √((p_a^(1 - p_a^)/n_a) + (p_b^(1 - p_b^)/n_b))

We are given;

p_a^ = 0.48

n_a = 80

p_b^ = 0.13

n_b = 66

Thus;

σ_(A - B) = √((0.48(1 - 0.48)/80) + (0.14(1 - 0.13)/66))

σ_(A - B) = √0.00496545455

σ_(A - B) = 0.070

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